Hey tommly.
The change of base rule says that log_a(x) = log_b(x)/log_b(a) for bases a and b.
Hint: Try changing the LHS to log_2(x) given that it is log_5(x) by using this formula.
My daughter has the following question on her home work. Although I'm pretty good on all the calculus for the life of me I can not figure this out and am obviously doing some thing wrong. If you can help that would be great.
The question is:
Using the log change of base rule solve for x:
Log _{5}^{6x+4} = Log _{2x49}
Should be simple...right?
Thanks
doing the Left hand side I then get
Log _{2x} (6x+4)/Log _{2x} 5 = Log _{2x}49
That does not really help me.
I've tried changing the RHS to Log 5 and that does not help me either. I end up with a Log multiplying a Log both the the variable x in it......
obviously missing something
Hello, tommiy!
Your use of [SUB] and [SUP] is confusing.
If it is [1], we have: .
. . which becomes: .
And I see no way to solve for
If it is [2], we have: .
This is a transcendental equation.
It cannot be solved for
From what course did this problem arise?
And who would assign such a frustrating problem?