3e^(4x)-9e^(2x)-15=0 I tried to solve this question and I couldn't finish solving it. Can you please show me how i would do this?
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Originally Posted by paigesisco 3e^(4x)-9e^(2x)-15=0 I tried to solve this question and I couldn't finish solving it. Can you please show me how i would do this? Can you solve $\displaystyle 3y^2-9y-15=0~?$
I have tried but my answer comes out wrong, can you please help?
Originally Posted by paigesisco I have tried but my answer comes out wrong, can you please help? When solving it plato's way did you remember to find x after you found the value(s) of y?
Yes i did that. Can you solve the equation out for me fully so that i can understand it in former questions
Originally Posted by paigesisco Yes i did that. Can you solve the equation out for me fully so that i can understand it in former questions You should get $\displaystyle e^{2x}=\frac{3+\sqrt{29}}{2}$.
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