log(x+1) - log(x-1) = -2 Not sure if I am supposed to add 2 to the other side. If I do, what is there to do next?
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$\displaystyle \log (a + b) - \log (c + d) = \log \frac{a+b}{c+d}$
log(x+1) - log(x-1) = log [ (x+1)/(x-1)]= -2 that gives (x+1)/(x-1) = e^-2 Now you can proceed to solution
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