Is this a simultaneous, quadratic equation? What am I doing wrong?

It's been overs ten years since my last calculus course, and I think I've regressed back to a pre-algebra level. Not looking for an answer here, just help getting started.

What I **think** I have here is a simultaneous equation, but I'm not sure... as I try to work it out, I keep getting stuck with what seems like a quadratic equation. I'm sure I'm wrong on one or both counts, so can someone lend some perspective?

**The problem:**

I'm trying to design a cylinder with dimensions proportional to a larger cylinder.

The diameter of the original cylinder = 26.24 ft

The height of the original cylinder = 12.08 ft

This gives a diameter to height ratio of **2.172**.

I'd like to find the dimensions necessary to design a 0.668 cubic foot cylinder while maintaining the proportions of the larger cylinder, so I've come up with the following simultaneous equations:

diameter = X (in feet)

height = Y (in feet)

**(X/2)**^{2} * PI * Y = 0.668 cubic feet

X/Y = 2.172

I've tried to solve for X in the first equation...

X^{2}/4 * PI * Y = 0.668

Multiply LHS and RHS by 4 to clear demoninator

X^{2} * 4PI * 4Y = 2.672

Divide both sides by 4PI

X^{2 }* 4Y = 2.672 / 4PI

X^{2} * 4Y = 0.2126

Divide both sides by 4Y

X^{2} = 0.05316 / Y

X = SQRT (0.05316 / Y)

... and then insert it into the second equation...

(SQRT (0.05316 / Y)) / Y = 2.172

Multiply RHS by Y to clear denominator

(SQRT (0.05316 / Y)) = 2.172Y

Square both sides

(SQRT (0.05316 / Y))^{2} = 4.7176Y^{2}

0.05316 / Y = 4.7176Y^{2 }Multiply both sides by Y

0.05316 = 4.7176Y^{3}

Y^{3} = 0.0113 feet

Y = 0.224 feet

This would make the height of the cylinder 2.69 inches, and the diameter 5.84 inches. This isn't right.

I'm sure this is simple and that I'm making it overly complex. Still, any help would be really appreciated. Thanks!

Re: Is this a simultaneous, quadratic equation? What am I doing wrong?

Quote:

Originally Posted by

**Math441100** It's been overs ten years since my last calculus course, and I think I've regressed back to a pre-algebra level. Not looking for an answer here, just help getting started.

What I **think** I have here is a simultaneous equation, but I'm not sure... as I try to work it out, I keep getting stuck with what seems like a quadratic equation. I'm sure I'm wrong on one or both counts, so can someone lend some perspective?

**The problem:**

I'm trying to design a cylinder with dimensions proportional to a larger cylinder.

The diameter of the original cylinder = 26.24 ft

The height of the original cylinder = 12.08 ft

This gives a diameter to height ratio of **2.172**.

I'd like to find the dimensions necessary to design a 0.668 cubic foot cylinder while maintaining the proportions of the larger cylinder, so I've come up with the following simultaneous equations:

diameter = X (in feet)

height = Y (in feet)

**(X/2)**^{2} * PI * Y = 0.668 cubic feet

X/Y = 2.172

I've tried to solve for X in the first equation...

X^{2}/4 * PI * Y = 0.668

X^{2} * PI * 4Y = 4 * 0.668 = 2.672

X^{2 }* 4Y = 2.672 / PI

X^{2} = 0.2126 / 4Y

X^{2} = 0.05316 / Y

X = SQRT (0.05316 / Y)

... and then insert it into the second equation...

(SQRT (0.05316 / Y)) / Y = 2.172

(SQRT (0.05316 / Y)) = 2.172Y

(SQRT (0.05316 / Y))^{2} = 4.7176Y^{2}

0.05316 = 4.7176Y^{2 }/ Y

0.05316 = 4.7176Y

Y = 0.0113 feet

This would make the height of the cylinder 0.135 inches, and the diameter 0.35 inches. This isn't right.

I'm sure this is simple and that I'm making it overly complex. Still, any help would be really appreciated. Thanks!

The second equation for X: You have an extra 4 on the RHS.

The fourth equation for Y: You need to multiply both sides of the equation to clear out the denominator on the RHS. It looks like you divided.

-Dan