# Is this a simultaneous, quadratic equation? What am I doing wrong?

• Mar 5th 2013, 03:20 PM
Math441100
Is this a simultaneous, quadratic equation? What am I doing wrong?
It's been overs ten years since my last calculus course, and I think I've regressed back to a pre-algebra level. Not looking for an answer here, just help getting started.

What I think I have here is a simultaneous equation, but I'm not sure... as I try to work it out, I keep getting stuck with what seems like a quadratic equation. I'm sure I'm wrong on one or both counts, so can someone lend some perspective?

The problem:

I'm trying to design a cylinder with dimensions proportional to a larger cylinder.

The diameter of the original cylinder = 26.24 ft
The height of the original cylinder = 12.08 ft

This gives a diameter to height ratio of 2.172.

I'd like to find the dimensions necessary to design a 0.668 cubic foot cylinder while maintaining the proportions of the larger cylinder, so I've come up with the following simultaneous equations:

diameter = X (in feet)
height = Y (in feet)

(X/2)2 * PI * Y = 0.668 cubic feet
X/Y = 2.172

I've tried to solve for X in the first equation...

X2/4 * PI * Y = 0.668
Multiply LHS and RHS by 4 to clear demoninator
X2 * 4PI * 4Y = 2.672
Divide both sides by 4PI
X2 * 4Y = 2.672 / 4PI
X2 * 4Y = 0.2126
Divide both sides by 4Y
X2
= 0.05316 / Y
X = SQRT (0.05316 / Y)

... and then insert it into the second equation...

(SQRT (0.05316 / Y)) / Y = 2.172
Multiply RHS by Y to clear denominator
(SQRT (0.05316 / Y)) = 2.172Y
Square both sides
(SQRT (0.05316 / Y))2 = 4.7176Y2
0.05316 / Y = 4.7176Y2
Multiply both sides by Y
0.05316 = 4.7176Y3
Y3 = 0.0113 feet
Y = 0.224 feet

This would make the height of the cylinder 2.69 inches, and the diameter 5.84 inches. This isn't right.

I'm sure this is simple and that I'm making it overly complex. Still, any help would be really appreciated. Thanks!
• Mar 5th 2013, 03:41 PM
topsquark
Re: Is this a simultaneous, quadratic equation? What am I doing wrong?
Quote:

Originally Posted by Math441100
It's been overs ten years since my last calculus course, and I think I've regressed back to a pre-algebra level. Not looking for an answer here, just help getting started.

What I think I have here is a simultaneous equation, but I'm not sure... as I try to work it out, I keep getting stuck with what seems like a quadratic equation. I'm sure I'm wrong on one or both counts, so can someone lend some perspective?

The problem:

I'm trying to design a cylinder with dimensions proportional to a larger cylinder.

The diameter of the original cylinder = 26.24 ft
The height of the original cylinder = 12.08 ft

This gives a diameter to height ratio of 2.172.

I'd like to find the dimensions necessary to design a 0.668 cubic foot cylinder while maintaining the proportions of the larger cylinder, so I've come up with the following simultaneous equations:

diameter = X (in feet)
height = Y (in feet)

(X/2)2 * PI * Y = 0.668 cubic feet
X/Y = 2.172

I've tried to solve for X in the first equation...

X2/4 * PI * Y = 0.668
X2 * PI * 4Y = 4 * 0.668 = 2.672
X2 * 4Y = 2.672 / PI
X2 = 0.2126 / 4Y
X2
= 0.05316 / Y
X = SQRT (0.05316 / Y)

... and then insert it into the second equation...

(SQRT (0.05316 / Y)) / Y = 2.172
(SQRT (0.05316 / Y)) = 2.172Y
(SQRT (0.05316 / Y))2 = 4.7176Y2
0.05316 = 4.7176Y2 / Y
0.05316 = 4.7176Y
Y = 0.0113 feet

This would make the height of the cylinder 0.135 inches, and the diameter 0.35 inches. This isn't right.

I'm sure this is simple and that I'm making it overly complex. Still, any help would be really appreciated. Thanks!

The second equation for X: You have an extra 4 on the RHS.

The fourth equation for Y: You need to multiply both sides of the equation to clear out the denominator on the RHS. It looks like you divided.

-Dan