To be exact, "Find a polynomial function with real coefficients that has the given zeros." My instructor just glazed over this in lecture and I don't see how the book is getting its answers. What exactly is the process to doing this? An example set of given zeros:
For your polynomial function to have real coefficients, all nonreal solutions will occur as complex conjugates. So you know that x = 4, x = -3i and x = 3i will all be zeroes of the polynomial. That means a polynomial that works isOriginally Posted by zsf1990
To be exact, "Find a polynomial function with real coefficients that has the given zeros." My instructor just glazed over this in lecture and I don't see how the book is getting its answers. What exactly is the process to doing this? An example set of given zeros:
![\displaystyle \begin{align*} y &= a\left( x - 4 \right) \left[ x - (-3i) \right] \left( x - 3i \right) \\ &= a \left( x - 4 \right) \left( x^2 + 9 \right) \end{align*}](http://latex.codecogs.com/png.latex?\displaystyle \begin{align*} y &= a\left( x - 4 \right) \left[ x - (-3i) \right] \left( x - 3i \right) \\ &= a \left( x - 4 \right) \left( x^2 + 9 \right) \end{align*})
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