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**HallsofIvy** **You** were the one who decided to make $\displaystyle t= 3^x$! And once you found that t= 27 and t= 1 are roots, you should immediately realize that $\displaystyle 3^x= 27$ and $\displaystyle 3^x= 3$. Isn't it clear what x must be?

(**If** it were something more complicated, say $\displaystyle 3^x= 25$, you could use a logarithm: $\displaystyle log(3^x)= xlog(3)= log(25)$ and then $\displaystyle x= \frac{log(25)}{log(3)}$ where the logarithm can be to any convenient base. But since both "3" and "27" are powers of 3, you were probably not intended to do that.)