Results 1 to 4 of 4

Math Help - sketch the graph y=√(16-y^2)

  1. #1
    Newbie
    Joined
    Feb 2013
    From
    Australia
    Posts
    2

    sketch the graph y=√(16-y^2)

    thanks
    Follow Math Help Forum on Facebook and Google+

  2. #2
    Newbie
    Joined
    Feb 2013
    From
    Australia
    Posts
    5

    Re: sketch the graph y=√(16-y^2)

    Are you sure it is 16-Y^2? not X^2
    anyway i graphed X^2 and it looks like a bowl upside down
    Roots:-4,4
    y int:4
    Follow Math Help Forum on Facebook and Google+

  3. #3
    Senior Member Educated's Avatar
    Joined
    Aug 2010
    From
    New Zealand
    Posts
    433
    Thanks
    12

    Re: sketch the graph y=√(16-y^2)

    If the equation is y=\sqrt{16-x^2}

    Then recall that the equation of a circle is x^2 + y^2 = k^2

    If you re-arrange for y, then you get your equation, but only the positive half.
    Follow Math Help Forum on Facebook and Google+

  4. #4
    MHF Contributor
    Prove It's Avatar
    Joined
    Aug 2008
    Posts
    11,564
    Thanks
    1425

    Re: sketch the graph y=√(16-y^2)

    The OP fixed the mistake by posting again. It's actually \displaystyle \begin{align*} x = \sqrt{16 - y^2} \end{align*}. This is a semicircle centred at the origin of radius 4 units, taking on only positive values for x.
    Follow Math Help Forum on Facebook and Google+

Similar Math Help Forum Discussions

  1. Solve and Graph 13x^2+ 6√3xy + 7y^2 16 = 0
    Posted in the Advanced Algebra Forum
    Replies: 5
    Last Post: March 22nd 2011, 03:16 PM
  2. please help sketch the graph
    Posted in the Calculus Forum
    Replies: 1
    Last Post: March 23rd 2010, 07:22 AM
  3. Sketch the graph of...
    Posted in the Pre-Calculus Forum
    Replies: 1
    Last Post: August 6th 2009, 06:50 PM
  4. Replies: 2
    Last Post: February 14th 2009, 12:12 PM
  5. Replies: 2
    Last Post: June 17th 2008, 01:04 PM

Search Tags


/mathhelpforum @mathhelpforum