# sketch the graph y=√(16-y^2)

• Feb 23rd 2013, 05:55 PM
cityskyline
sketch the graph y=√(16-y^2)
thanks :)
• Feb 23rd 2013, 06:00 PM
Zashmar
Re: sketch the graph y=√(16-y^2)
Are you sure it is 16-Y^2? not X^2
anyway i graphed X^2 and it looks like a bowl upside down
Roots:-4,4
y int:4
• Feb 23rd 2013, 06:04 PM
Educated
Re: sketch the graph y=√(16-y^2)
If the equation is $y=\sqrt{16-x^2}$

Then recall that the equation of a circle is $x^2 + y^2 = k^2$

If you re-arrange for y, then you get your equation, but only the positive half.
• Feb 23rd 2013, 06:37 PM
Prove It
Re: sketch the graph y=√(16-y^2)
The OP fixed the mistake by posting again. It's actually \displaystyle \begin{align*} x = \sqrt{16 - y^2} \end{align*}. This is a semicircle centred at the origin of radius 4 units, taking on only positive values for x.