Looking at some of the older stuff and for ∫1/10(x)(6x^2-15) dx became 1/120 ∫12x(6x^2-15) dx, how was the 1/120 ∫12x arrived at?

Results 1 to 8 of 8

- February 22nd 2013, 01:20 PM #1

- Joined
- Feb 2013
- From
- Ireland
- Posts
- 15

- February 22nd 2013, 01:43 PM #2

- Joined
- Feb 2013
- From
- Toronto
- Posts
- 3

- February 22nd 2013, 01:47 PM #3

- Joined
- Feb 2013
- From
- Ireland
- Posts
- 15

- February 22nd 2013, 01:49 PM #4

- Joined
- Feb 2013
- From
- Toronto
- Posts
- 3

- February 22nd 2013, 02:03 PM #5

- Joined
- Feb 2013
- From
- Ireland
- Posts
- 15

- February 22nd 2013, 02:16 PM #6

- Joined
- Feb 2013
- From
- Toronto
- Posts
- 3

## Re: Question

EDIT:

**1/120 ∫12x(6x^2-15) dx**

=1/120**∫ 72x^3-180x dx**I'm sorry i forgot that it was possible that you didn't cover u-substitution, which is just a method of integration and all you had to do was multiply it out and integrate the polynomial! sorry!

and 1/120 was probably to avoid fractions during integration

- February 22nd 2013, 11:55 PM #7

- Joined
- Feb 2013
- From
- Ireland
- Posts
- 15

- February 23rd 2013, 06:43 AM #8