Looking at some of the older stuff and for ∫1/10(x)(6x^2-15) dx became 1/120 ∫12x(6x^2-15) dx, how was the 1/120 ∫12x arrived at?

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- February 22nd 2013, 02:20 PM #1

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- February 22nd 2013, 02:43 PM #2

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- February 22nd 2013, 02:47 PM #3

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- February 22nd 2013, 02:49 PM #4

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- February 22nd 2013, 03:03 PM #5

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- February 22nd 2013, 03:16 PM #6

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## Re: Question

EDIT:

**1/120 ∫12x(6x^2-15) dx**

=1/120**∫ 72x^3-180x dx**I'm sorry i forgot that it was possible that you didn't cover u-substitution, which is just a method of integration and all you had to do was multiply it out and integrate the polynomial! sorry!

and 1/120 was probably to avoid fractions during integration

- February 23rd 2013, 12:55 AM #7

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- February 23rd 2013, 07:43 AM #8