I got problem with nr 39. If i understand right there shall be at limit x->2 because denominator. With other words if i understand correct i shall solve limit x->2 (2x+1)/(x-2) well i basicly got problem to solve that limit.
I got problem with nr 39. If i understand right there shall be at limit x->2 because denominator. With other words if i understand correct i shall solve limit x->2 (2x+1)/(x-2) well i basicly got problem to solve that limit.
1. A vertical asymptote occurs if the denominator of a quotient equals zero and the numerator unequals zero. With your example:
you'll get a vertical asymptote at x = 1
2. Re-write the equation by synthetic division:
Since
you'll get
3. The line with the equation y = 2 is the horizontal asymptote.
Thanks!
Just wanna correct u it was x-2 on denominator so vertical asymptot at x=2
so we rewrite the equation as 2+5/(x-2)
Edit: just a question. Should i also check lin x->-infinity aswell? In this problem it Will still be 2 but i should also check when lim x->-infinity? I am correct?
Some functions not all ...have asymptotes that are not vertical or horizontal .these are slant asymptotes...depending on your math carricculum you may or may not learnt them...the above theorem I mentioned is used to track them.
Minoas