Thread: How is this a limit

(x^2+16x+64)/(x+8)

So i factored and simplified to (x+8) from the left its negative infinity and the right positive infinity right? My textbook says its a limit with a value of 0 (lim x --> -8)

Also

lim x--> 3 = 1 / (x-3)^2 from both the left and right would be positive infinity if i understand limits right. My textbook says its not a limit.

Hey skg94.

For the second one, something is a limit if the limit exists from both sides with the same value. I think this should be a limit as well (does your question ask about 1/(x-3) instead?)

Originally Posted by skg94

(x^2+16x+64)/(x+8)

So i factored and simplified to (x+8) from the left its negative infinity and the right positive infinity right? My textbook says its a limit with a value of 0 (lim x --> -8)

Also

lim x--> 3 = 1 / (x-3)^2 from both the left and right would be positive infinity if i understand limits right. My textbook says its not a limit.

For the first one, the function is identical to everywhere except where because the function would be undefined. But the function will still approach the same value as it would in the function , because they are identical everywhere else.