1/ sqroot(x) - 1/2 / x-4

I first simplified by multiplying by 2sqroot(x) = 2-sqroot(x) / (x-4) (2sqroot(x)) than i was going to rationalize the numerator by multiplying by 2+ sqroot(x) but that seemed too complicated.

Where did i go wrong?

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- Feb 9th 2013, 10:09 PMskg94Factoring and rationalizing
1/ sqroot(x) - 1/2 / x-4

I first simplified by multiplying by 2sqroot(x) = 2-sqroot(x) / (x-4) (2sqroot(x)) than i was going to rationalize the numerator by multiplying by 2+ sqroot(x) but that seemed too complicated.

Where did i go wrong? - Feb 9th 2013, 10:24 PMearthboyRe: Factoring and rationalizing
- Feb 11th 2013, 09:34 PMskg94Re: Factoring and rationalizing
I dont know how to, but well i suppose its the same but its (1/rootx - 1/2 ) / (x-4)

- Feb 11th 2013, 10:29 PMSorobanRe: Factoring and rationalizing
Hello, skg94!

Quote:

I first simplified by multiplying by .and got: .

Then I was going to rationalize the numerator by multiplying by

but that seemed too complicated. . But did you try it?

Where did i go wrong? . Nowhere . . . your work is correct!

You would have: /

. . . . . . . . . . . . . .