Hi.idk how to solve that equation... Ik that i shall do 1000=x^2+10sinx. I need some tips. Its problem nr 45.

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- Feb 9th 2013, 05:48 AMPetrusEquation
Hi.idk how to solve that equation... Ik that i shall do 1000=x^2+10sinx. I need some tips. Its problem nr 45.

- Feb 9th 2013, 06:27 AMPlatoRe: Equation

Frankly I am a bit put out with your posting images and showing no effort what so ever. The last time, I spent time to help you work out the limits, only to be told "forget it, I have already done the problem".

So in the future, you learn to use LaTex to post your questions, no images. Or else don't expect a reply, especially if you do not show any effort. - Feb 9th 2013, 06:36 AMPetrusRe: Equation
Hello Plato.

Sorry about that but sometimes it just pop upp the way to solve it or i get an idé, its rude of me sometimes to forget to post of me that i solved. Well mostly like 90% of Times' i studdy i dont sit infront of pc and its anoying to type( im using smartphone). Pc Will just distraktion me from studdy. Ohh well im sorry but picture is alot more easy and faster.Well im sorry but this is only way i can get help... Unfortenetly i dont have any other that know good math. - Feb 9th 2013, 07:16 AMabenderRe: Equation
First off, just own up to your mistake, apologize and sincerely work on fixing it in the future. Plato -- who has never charged you or anyone on here any money -- more than deserves the courtesy, don't you think? Don't make excuses. Owning up to mistakes is a sign of one's character and personal strength.

Find a value for $\displaystyle x$ such that $\displaystyle f(x)<1000$ and call this value $\displaystyle a$. Find another value for $\displaystyle x$ such that $\displaystyle f(x)>1000$ and call this value $\displaystyle b$.

For example, let $\displaystyle a=0$ and $\displaystyle b=12\pi$.

$\displaystyle f(0) = 0 <1000 $ and $\displaystyle f\left(12\pi\right) \approx 1421.22 > 1000 $.

$\displaystyle f$ is real-valued and continuous on $\displaystyle [0,12\pi]$, right?

Now what does the Intermediate Value Theorem say? - Feb 10th 2013, 04:24 AMHallsofIvyRe: Equation
Do you understand that this problem does NOT ask you to solve 1000=x^2+10sinx?

- Feb 10th 2013, 06:53 AMPetrusRe: Equation
Yes i did and solved it:) i Will just prove thqt any number on thqt intervall Will give me the solve. I Will not answer like x=3 but i Will prove thqt there is an answer in the intervall. Thats what i did understand