A simple plot of the points shows that this is not a parallelogram...
Hello. Pre-cal practice work for test tomorrow.
Problem gives us these coordinates: A(1,2), B(5,2), C(3,6), D(5, -3)
I graphed it. How are we supposed to find the area with these coordinates?
I know the answer is 16, because I checked the back of the book. I would like to know how to get that answer.
Thank you
Oh yes, I apologize for the misconveniance.. I will correct this when I get back to my room to access my pre-cal book.
Hello, theadage!
Please check for typos.
The problem doesn't make sense.
Problem gives us these coordinates: A(1,2), B(5,2), C(3,6), D(5, -3) .[1]
I graphed it. How are we supposed to find the area with these coordinates?
I know the answer is 16, because I checked the back of the book. .[2]
I would like to know how to get that answer. . So would I!
[1] The vertices are usually labeled in order around the parallelogram.
. . .The given coordinates are not.
. . .Besides, they do not form a parallelogram.
[2] The area is not 16.Code:| | C | o | *:* | * :4* | * : * |Ao * * * oB | * 4 * - + - - * - *5 - - | * * | o | D |
Triangle has base 4 and height 4.
. . Its area is
Triangle has base 4 and height 5.
. . Its area is
The total area is