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Math Help - Limits

  1. #1
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    Limits

    Hi i got problem with solving number 47
    My progress: i simplify to x^2-1
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    Last edited by Petrus; February 5th 2013 at 03:26 AM.
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  2. #2
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    Re: Limits

    Whenever you deal with absolute values, it helps to write it as its hybrid function form...
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    Re: Limits

    What u mean with hybrid function form?
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    Re: Limits

    \displaystyle \begin{align*} |X| = \begin{cases} \phantom{-}X \textrm{ if } X \geq 0 \\ -X \textrm{ if } X < 0  \end{cases} \end{align*}
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    Re: Limits

    lx-1l x if>_1 and -x if x<1 i cant se a point
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    Re: Limits

    So approaching from the left (where \displaystyle \begin{align*} x < 1 \end{align*}) your function will be \displaystyle \begin{align*} \frac{x^2 - 1}{-(x - 1)} \end{align*}. Simplify and subsitute x = 1 to find the left hand limit.

    What do you think you would have to do for the right hand limit?
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  7. #7
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    Re: Limits

    (X^2-1)/(x-1) with other words if we factor ((x-1)(x+1))/(x-1) so we got -2 from left and 2 for right? I am correct?
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  8. #8
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    Re: Limits

    Correct
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