# Math Help - Limits

1. ## Limits

Hi i got problem with solving number 47
My progress: i simplify to x^2-1

2. ## Re: Limits

Whenever you deal with absolute values, it helps to write it as its hybrid function form...

3. ## Re: Limits

What u mean with hybrid function form?

4. ## Re: Limits

\displaystyle \begin{align*} |X| = \begin{cases} \phantom{-}X \textrm{ if } X \geq 0 \\ -X \textrm{ if } X < 0 \end{cases} \end{align*}

5. ## Re: Limits

lx-1l x if>_1 and -x if x<1 i cant se a point

6. ## Re: Limits

So approaching from the left (where \displaystyle \begin{align*} x < 1 \end{align*}) your function will be \displaystyle \begin{align*} \frac{x^2 - 1}{-(x - 1)} \end{align*}. Simplify and subsitute x = 1 to find the left hand limit.

What do you think you would have to do for the right hand limit?

7. ## Re: Limits

(X^2-1)/(x-1) with other words if we factor ((x-1)(x+1))/(x-1) so we got -2 from left and 2 for right? I am correct?

Correct