Thread: Finding what point is guaranteed to be on the graph.

I have several problems that look like this.
Could someone walk me through the first one:

The graph of the function y=f(x) contains the point (2,5)

What point is guaranteed to be on the graph of y=f(x+3)-5 ?

Originally Posted by sy416

The graph of the function y=f(x) contains the point (2,5) What point is guaranteed to be on the graph of y=f(x+3)-5 ?

From the given you know that . WHY?

What value of will introduce into ?

Then what point do you have?

Originally Posted by Plato

From the given you know that . WHY?

What value of will introduce into ?

Then what point do you have?

I don't know. It confuses me with the y's and the f(x)'s

Originally Posted by sy416

I don't know. It confuses me with the y's and the f(x)'s

OK. Forget the y's and the f(x)'s

You can surely answer this question.
What value of will introduce into ?

Originally Posted by Plato

OK. Forget the y's and the f(x)'s

You can surely answer this question.
What value of will introduce into ?

2?

Originally Posted by sy416

2?

NO! f(2+3)=f(5) f(2). Try again!

Originally Posted by Plato

NO! f(2+3)=f(5) f(2). Try again!

BUt that's the thing I don't know how to find the x value that will introduce f(2). How do I do it? I need help understanding the problem.

Wait I think I have it...

Ohh! I have to choose an x value that will bring it back to f(2) .. soo... x= -1

y= f(-1+3)-5

y= f(2) - 5

y= 5-5

y=0

(-1,0)

Thank you!

Originally Posted by sy416

BUt that's the thing I don't know how to find the x value that will introduce f(2). How do I do it? I need help understanding the problem.

I don't think that you are ready to do this question.

If you look at the answer in the 'back-of-the-book' it would be .

Originally Posted by Plato

I don't think that you are ready to do this question.

If you look at the answer in the 'back-of-the-book' it would be .

Nah I got it (scroll up). Thanks.