Vertex of 0,3

Focus of 0,0

Formula for parabola:

y = a(x - h)^2 + k

I assume that h = 0, k = 3 (the vertex)

how does the focus factor into this equation? thanks.

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- Jan 28th 2013, 09:30 AMtogoTrying to find equation for parabola
Vertex of 0,3

Focus of 0,0

Formula for parabola:

y = a(x - h)^2 + k

I assume that h = 0, k = 3 (the vertex)

how does the focus factor into this equation? thanks. - Jan 28th 2013, 11:38 AMHallsofIvyRe: Trying to find equation for parabola
If you write the eqation of a parabola as , the same as your formula with [itex]h= x_0[/itex], [itex]k= y_0[/tex], where [itex](x_0, y_0)[/itex] is the vertex, then the focal length is f= 1/4a.Parabola - Wikipedia, the free encyclopedia

Saying that the vertex is at (0, 3) and the focus is at (0, 0) means that the focal length is f=1/4a= 3 so that 4a= 1/3, a= 1/12. Of course, because the focus is**below**the vertex, the parabola opens**downward**, so a is negative.