Dear all!

Please, how do I get that for x>1 all $\displaystyle arctan\frac{x+1}{x-1}+arctan(x)=arctan2 + arctan3$

Many thanks!

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- Jan 22nd 2013, 03:19 AMBooarcten2+arctan3
Dear all!

Please, how do I get that for x>1 all $\displaystyle arctan\frac{x+1}{x-1}+arctan(x)=arctan2 + arctan3$

Many thanks! - Jan 22nd 2013, 05:52 AMtopsquarkRe: arcten2+arctan3