Expanding and subtracting binomials
I'm working on expanding binomials and I currently understand how to expand basic ones using the binomial theorem. But due to transferring to my Precalc class late, I missed the lecture on them. Could someone explain how to expand and simplify this expression using the binomial theorem?
^4 + 5(x-3)^2)
Thanks in advance!
Re: Expanding and subtracting binomials
Quote:
Originally Posted by
zsf1990
I'm working on expanding binomials and I currently understand how to expand basic ones using the binomial theorem. But due to transferring to my Precalc class late, I missed the lecture on them. Could someone explain how to expand and simplify this expression using the binomial theorem?
Thanks in advance!
OH, Come on!
![2(x-3)^4 + 5(x-3)^2=(x-3)^2[2(x-3)^2+5][](http://latex.codecogs.com/png.latex?2(x-3)^4 + 5(x-3)^2=(x-3)^2[2(x-3)^2+5][)
Re: Expanding and subtracting binomials
I don't think I understand what you mean. The book gives
as the solution. I got
by applying the 2 and 5 after expanding, then combining like terms. I'm not sure where I messed up.
Re: Expanding and subtracting binomials
Quote:
Originally Posted by
zsf1990
I don't think I understand what you mean. The book gives

as the solution. I got

by applying the 2 and 5 after expanding, then combining like terms. I'm not sure where I messed up.
May I ask you, if you know the answer then why are you asking?
Re: Expanding and subtracting binomials
Knowing the answer does me no good if I don't know how to get there. I know how to expand the binomial
and how to subtract the two expanded terms. What I don't understand is what to do with the 2 and the 5.
Re: Expanding and subtracting binomials
Quote:
Originally Posted by
zsf1990
Knowing the answer does me no good if I don't know how to get there. I know how to expand the binomial
^4)
and how to subtract the two expanded terms. What I don't understand is what to do with the 2 and the 5.
Once you expand each of the terms using the Binomial Theorem, multiply each term through by 2 or 5 (depending on which number is out the front).
However, Plato's advice gives you an easier alternative form to work with.