Expanding and subtracting binomials

I'm working on expanding binomials and I currently understand how to expand basic ones using the binomial theorem. But due to transferring to my Precalc class late, I missed the lecture on them. Could someone explain how to expand and simplify this expression using the binomial theorem?

Thanks in advance!

Re: Expanding and subtracting binomials

Quote:

Originally Posted by

**zsf1990** I'm working on expanding binomials and I currently understand how to expand basic ones using the binomial theorem. But due to transferring to my Precalc class late, I missed the lecture on them. Could someone explain how to expand and simplify this expression using the binomial theorem?

Thanks in advance!

OH, Come on!

Re: Expanding and subtracting binomials

I don't think I understand what you mean. The book gives as the solution. I got by applying the 2 and 5 after expanding, then combining like terms. I'm not sure where I messed up.

Re: Expanding and subtracting binomials

Quote:

Originally Posted by

**zsf1990** I don't think I understand what you mean. The book gives

as the solution. I got

by applying the 2 and 5 after expanding, then combining like terms. I'm not sure where I messed up.

May I ask you, if you know the answer then why are you asking?

Re: Expanding and subtracting binomials

Knowing the answer does me no good if I don't know how to get there. I know how to expand the binomial and how to subtract the two expanded terms. What I don't understand is what to do with the 2 and the 5.

Re: Expanding and subtracting binomials

Quote:

Originally Posted by

**zsf1990** Knowing the answer does me no good if I don't know how to get there. I know how to expand the binomial

and how to subtract the two expanded terms. What I don't understand is what to do with the 2 and the 5.

Once you expand each of the terms using the Binomial Theorem, multiply each term through by 2 or 5 (depending on which number is out the front).

However, Plato's advice gives you an easier alternative form to work with.