Let $\displaystyle m=\frac{\sqrt{10^{4024}-1}}{3}$

Find the $\displaystyle 2013th$ digit after the decimal point in the expression of \sqrt{m}

It seems a similar problem.

xkcd • View topic - math problem - driving me crazy

But I don't think so. I can't write m to $\displaystyle (\sqrt{a}+\sqrt{b})^n$ a,b,n is integer numbers