Thread: arctan

Dear All!
Pleas,e coudl someone help me to get
f(x)=-pi/4 for x<1
and
f(x)=arctan2+arctan3 for x>1



Many thanks!!!

you have


you put Tan everywhere


Solve the quadratic formula, you end up with x = 0 and x = (-1)

Originally Posted by Barioth

you have


you put Tan everywhere


Sorry about the <br/> I have no idea why these keep apearing :(

As you can I got rid of the <br/> in your post.
That happens if a linefeed in the code. This like this:

Your code should look like
[tex]\\ \frac{-\pi}{4}= \arctan{\frac{(x+1)}{(x-1)}} +\arctan(x)\\[/tex]
you put Tan everywhere
[TEX]\\\tan\frac{-\pi}{4} = \frac{(x+1)}{(x-1)} +(x)\\-1 = \frac{(x+1)}{(x-1)} +(x)\\0 = \frac{(x+1}{x-1} +(x) + 1[/TEX]

Thanks for the info!

Hello!
Many thanks!
But, I should not know in advance that the result is pi/4! I have to calculate it...how?
P.s. Please, can U tell me how did U got rid of arctans putting tan in front of arctan?
Many thanks!!!