Results 1 to 3 of 3
Like Tree3Thanks
  • 2 Post By Barioth
  • 1 Post By topsquark

Math Help - f(x)=e^((lnx)(1-lnx))

  1. #1
    Boo
    Boo is offline
    Junior Member
    Joined
    Jan 2013
    From
    Pizza
    Posts
    57

    f(x)=e^((lnx)(1-lnx))

    Dear All!
    please, if we have

    f(x)=e^{lnx(1-lnx)}

    How do we get local masimums and points of inflection?

    I tried:

    e^{lnx}=x

    f(x)=x^{(1-lnx)}...

    I got f(x)=\frac{x}{x^{lnx}}

    what now??? many thanks!
    Last edited by Boo; January 16th 2013 at 06:18 AM.
    Follow Math Help Forum on Facebook and Google+

  2. #2
    Junior Member Barioth's Avatar
    Joined
    Jan 2013
    From
    Canada
    Posts
    54
    Thanks
    16

    Re: f(x)=e^((lnx)(1-lnx))

    Do find the maximums and points of inflection I would derivate it now, have you seen derivate yet?

    edit: It would been ezier (for me..) to derivate the first equation that you gave. but thats just how I leanred my derivate
    Last edited by Barioth; January 16th 2013 at 09:20 AM.
    Thanks from topsquark and MarkFL
    Follow Math Help Forum on Facebook and Google+

  3. #3
    Forum Admin topsquark's Avatar
    Joined
    Jan 2006
    From
    Wellsville, NY
    Posts
    10,211
    Thanks
    419
    Awards
    1

    Re: f(x)=e^((lnx)(1-lnx))

    Quote Originally Posted by Barioth View Post
    Do find the maximums and points of inflection I would derivate it now, have you seen derivate yet?

    edit: It would been ezier (for me..) to derivate the first equation that you gave. but thats just how I leanred my derivate
    I agree totally with Barioth. It's easier in this case to take the derivative of the function before "simplifying" it.

    -Dan
    Thanks from MarkFL
    Follow Math Help Forum on Facebook and Google+

Search Tags


/mathhelpforum @mathhelpforum