# Math Help - f(x)=e^((lnx)(1-lnx))

1. ## f(x)=e^((lnx)(1-lnx))

Dear All!

$f(x)=e^{lnx(1-lnx)}$

How do we get local masimums and points of inflection?

I tried:

$e^{lnx}=x$

$f(x)=x^{(1-lnx)}$...

I got $f(x)=\frac{x}{x^{lnx}}$

what now??? many thanks!

2. ## Re: f(x)=e^((lnx)(1-lnx))

Do find the maximums and points of inflection I would derivate it now, have you seen derivate yet?

edit: It would been ezier (for me..) to derivate the first equation that you gave. but thats just how I leanred my derivate

3. ## Re: f(x)=e^((lnx)(1-lnx))

Originally Posted by Barioth
Do find the maximums and points of inflection I would derivate it now, have you seen derivate yet?

edit: It would been ezier (for me..) to derivate the first equation that you gave. but thats just how I leanred my derivate
I agree totally with Barioth. It's easier in this case to take the derivative of the function before "simplifying" it.

-Dan