How Do I Find X and Y If Hypotenuse is Given (Trigonometry)

**Vince604** · January 13th 2013, 08:50 PM

Find the length of Y, to the nearest tenth.

I have no idea how to find!! Help please

**Prove It** · January 13th 2013, 08:55 PM

If you look from the $\displaystyle \begin{align*} 27^{\circ} \end{align*}$ angle, then you set up your ratio as $\displaystyle \begin{align*} \sin{\left( 27^{\circ} \right)} = \frac{y}{6.2} \end{align*}$ and solve for y.

If you look from the $\displaystyle \begin{align*} 63^{\circ} \end{align*}$ angle, then you set up your ratio as $\displaystyle \begin{align*} \cos{ \left( 63^{\circ} \right)} = \frac{y}{6.2} \end{align*}$ and solve for y.

**Vince604** · January 13th 2013, 10:01 PM

Originally Posted by Prove It

If you look from the $\displaystyle \begin{align*} 27^{\circ} \end{align*}$ angle, then you set up your ratio as $\displaystyle \begin{align*} \sin{\left( 27^{\circ} \right)} = \frac{y}{6.2} \end{align*}$ and solve for y.

If you look from the $\displaystyle \begin{align*} 63^{\circ} \end{align*}$ angle, then you set up your ratio as $\displaystyle \begin{align*} \cos{ \left( 63^{\circ} \right)} = \frac{y}{6.2} \end{align*}$ and solve for y.

for 27, would it be sin (27) / 6.2? i really have no clue what to do...

**Prove It** · January 14th 2013, 06:08 PM

You can see that y has been DIVIDED by 6.2, so to undo this, you need to MULTIPLY both sides by 6.2

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