# How Do I Find X and Y If Hypotenuse is Given (Trigonometry)

• Jan 13th 2013, 08:50 PM
Vince604
How Do I Find X and Y If Hypotenuse is Given (Trigonometry)
Find the length of Y, to the nearest tenth.

http://i218.photobucket.com/albums/c...ps333f226b.jpg

I have no idea how to find!! Help please :)
• Jan 13th 2013, 08:55 PM
Prove It
Re: How Do I Find X and Y If Hypotenuse is Given (Trigonometry)
If you look from the \displaystyle \displaystyle \begin{align*} 27^{\circ} \end{align*} angle, then you set up your ratio as \displaystyle \displaystyle \begin{align*} \sin{\left( 27^{\circ} \right)} = \frac{y}{6.2} \end{align*} and solve for y.

If you look from the \displaystyle \displaystyle \begin{align*} 63^{\circ} \end{align*} angle, then you set up your ratio as \displaystyle \displaystyle \begin{align*} \cos{ \left( 63^{\circ} \right)} = \frac{y}{6.2} \end{align*} and solve for y.
• Jan 13th 2013, 10:01 PM
Vince604
Re: How Do I Find X and Y If Hypotenuse is Given (Trigonometry)
Quote:

Originally Posted by Prove It
If you look from the \displaystyle \displaystyle \begin{align*} 27^{\circ} \end{align*} angle, then you set up your ratio as \displaystyle \displaystyle \begin{align*} \sin{\left( 27^{\circ} \right)} = \frac{y}{6.2} \end{align*} and solve for y.

If you look from the \displaystyle \displaystyle \begin{align*} 63^{\circ} \end{align*} angle, then you set up your ratio as \displaystyle \displaystyle \begin{align*} \cos{ \left( 63^{\circ} \right)} = \frac{y}{6.2} \end{align*} and solve for y.

for 27, would it be sin (27) / 6.2? i really have no clue what to do...
• Jan 14th 2013, 06:08 PM
Prove It
Re: How Do I Find X and Y If Hypotenuse is Given (Trigonometry)
You can see that y has been DIVIDED by 6.2, so to undo this, you need to MULTIPLY both sides by 6.2