I'm having some issues with the word problems. Can you show me how to do them.
Deturmine the number of difforent arrangements using the letters of the word ACCESSES that:
A. Begin with exactly two S's.
B Begin with at least two S's.
Yes, I understand that ACCESSES is 8!/ 2x2x3! ,because there is 8 letters and two C's, 3 S's, and 2 E's.
So for A, I count all the S's as one in the top half of the equaision like 6!/2x2 ( Now I know what I was doing wrong befor, I was counting the S's as 2 not 1). Then I subtract the equasion without any S's ,So 5!/2x2 ,with the first answer to get the final answer. To get 150, I finally got it right. Thankyou so much!