Here is the equation: cubic root(2562) * 16x=64x-3
I need to express both sides as a power with base 2, but no matter how i solve it, it never can make base 2.
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Hint: Recall that 16 = 2^4 and 64 = 2^6 with the fact (a^xy) = (a^x)^y.
Originally Posted by JarvisStu001 Here is the equation: cubic root(2562) * 16x=64x-3
You need to awake up to basic powers. thus . .
Got it, Thanks alot!
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