Here is the equation: cubic root(256^{2}) * 16^{x}=64^{x-3} I need to express both sides as a power with base 2, but no matter how i solve it, it never can make base 2. HELP!!
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Hey JarvisStu001. Hint: Recall that 16 = 2^4 and 64 = 2^6 with the fact (a^xy) = (a^x)^y.
Originally Posted by JarvisStu001 Here is the equation: cubic root(256^{2}) * 16^{x}=64^{x-3} You need to awake up to basic powers. $\displaystyle 256=2^8$ thus $\displaystyle 256^2=2^{16}$. $\displaystyle 16^x=2^{4x}~\&~64^{x-3}=2^{6x-18}$.
Got it, Thanks alot!
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