1. ## Simplify this equation.

y=2e^-(ln x) + 1

Hey, can someone help me simplify this equation.

2. You know that exp(ln(a)) = a? And r.ln(x) = ln(x^r), so -ln(x) = ln(1/x).

3. Originally Posted by TD!
You know that exp(ln(a)) = a? And r.ln(x) = ln(x^r), so -ln(x) = ln(1/x).
so...

y=2(1/x)+1
y=2/x +1
?

4. Originally Posted by Takkun
y=2e^-(ln x) + 1

Hey, can someone help me simplify this equation.
Or you could look at it this way:
$\displaystyle y = 2e^{-ln(x)} + 1 = \frac{2}{e^{ln(x)}} + 1$
and then use TD's trick: $\displaystyle e^{ln(a)} = a$.

(It isn't much different, but I prefer to have my exponents positive when possible.)

-Dan

5. Originally Posted by Takkun
so...

y=2(1/x)+1
y=2/x +1
?
Correct!

6. Originally Posted by Takkun
so...

y=2(1/x)+1
y=2/x +1
?
Yes, that's it.

-Dan