Find the limit .
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JoinedAug 2012FromMariborPosts19Re: Limit Problem
Dear All!
Please, could anyone help me with this:
Find number a is element of R so that the function f(x)=a; x<=0
( x^1/2-1)/(x^1/3-1); x>0
is continuous in R?
R: a=3/2
p.s. how to get latex here? I tried to write by tags, but it just showed the source, what I wrote, and not the nice latex text!
Hello!
Please, why is lim (x to 1) from the same function 3/2?
If we have 0^(1/2)=0
0^(1/3)=0 so we should have: -1/-1=1, ok,
but if we have lim(x to 1) then we should have:
1^(1/3) =1
1^(1/2)=1, isnt't it?
so how do we get 3/2 from this?
p.s. stil unclear how I can write in latex my questions, not only to quote what others wrote-also this unclear, do I have problem s with my pc?
Happy New Year and many thanks!
Do you understand this equality:
As for LaTex here is the code for the above.
[tex] \frac{{\sqrt x - 1}}{{\sqrt[3]{x} - 1}} = \frac{{\sqrt[3]{{x^2 }} + \sqrt[3]{x} + 1}}{{\sqrt x + 1}}~?[/tex] Click on the “go advanced” tab. On the toolbar you will see clicking on that give the LaTeX wraps, [tex] [/tex]. The code goes between them.
It definitely not your PC. You just have to learn the coding.
Also if you would not use the fonts and color, it makes your posts easier to read.