1. ## basic trigonometric identities

I don't know where to begin to do stuff like this-

if sec theta=3/2, find cos theta.

or
use the given information to determine the exact trig value

cos theta= -2/3, 90 degress<theta<180 degress; sin theta

2. Originally Posted by Liyo
I don't know where to begin to do stuff like this-

if sec theta=3/2, find cos theta.

or
use the given information to determine the exact trig value

cos theta= -2/3, 90 degress<theta<180 degress; sin theta
The first one isn't so much a trig identity as it is a definition:
$\displaystyle cos\theta=\frac{1}{sec\theta}=\frac{1}{3/2}=2/3$

For the second one, we use probably the most standard trig identity:
$\displaystyle sin^2\theta + cos^2\theta = 1$
So if we have the cosine...
$\displaystyle sin^2\theta+(-2/3)^2=1$
$\displaystyle sin^2\theta+4/9=1$
$\displaystyle sin^2\theta=5/9$
$\displaystyle sin\theta=\pm \sqrt{5/9}$

Now, we are looking for an angle between 90 and 180 degrees. The sine function is positive in this interval. So $\displaystyle sin\theta=\sqrt{5/9}$. Specifically, we will be finding a value for theta between 0 and 90 degrees, so we are considering the angle we will find to be a reference angle.

I don't know of any "nice" angle such that the sine of theta will be this value. So find theta using a calculator. Now, this is the reference angle measured from 180 degrees, so we subtract this angle from 180. I get about 131.8 degrees.

-Dan

3. if you're having trouble with it, just draw a picture and break the problem into smaller parts. you know that $\displaystyle cos$ is between 90 and 180 degrees. and that $\displaystyle cos \theta =-2/3$. so draw a picture. find the length of the other leg using the pythagorean theorem and find sin.