Polynomial Function

**vaironxxrd** · December 16th 2012, 05:43 PM

(a) List each Zero for ... $F(x) = 3(x-7)(x+3)^2$

I did the following $F(x) = \frac{3(x-7)(x+3)^2}{3} = \frac{0}{3}$

Now $(x-7)(x+3)(x+3) = 0$
The zeros are 7,-3 Multiplicity 2.

Correct?

**chiro** · December 17th 2012, 02:14 AM

Hey vaironxxrd.

Your answers are spot on.

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