(a) List each Zero for ... $\displaystyle F(x) = 3(x-7)(x+3)^2$

I did the following $\displaystyle F(x) = \frac{3(x-7)(x+3)^2}{3} = \frac{0}{3}$

Now $\displaystyle (x-7)(x+3)(x+3) = 0$

The zeros are 7,-3 Multiplicity 2.

Correct?

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- Dec 16th 2012, 04:43 PMvaironxxrdPolynomial Function
(a) List each Zero for ... $\displaystyle F(x) = 3(x-7)(x+3)^2$

I did the following $\displaystyle F(x) = \frac{3(x-7)(x+3)^2}{3} = \frac{0}{3}$

Now $\displaystyle (x-7)(x+3)(x+3) = 0$

The zeros are 7,-3 Multiplicity 2.

Correct? - Dec 17th 2012, 01:14 AMchiroRe: Polynomial Function
Hey vaironxxrd.

Your answers are spot on.