Honestly, its really hard to remember the cubic one,
but if you need it solved, click the link.
0=x^3 -3/4x +1/4 - Wolfram|Alpha
Hi - I am stuck on a question that requires me to find the 2nd point of intersection between a power function (x^3) and the tangent of the function at a given point (1/2, 1/8), which I determined to be y=3/4x - 1/4
I have combined the two equations and created a 3rd order trinomial 0=x^3 -3/4x +1/4. My problem is that I forget how to factor a trinomial with an odd power. Any help would be appreciated.
Thanks in advance.
Honestly, its really hard to remember the cubic one,
but if you need it solved, click the link.
0=x^3 -3/4x +1/4 - Wolfram|Alpha
Thanks a tutor. I understand that the first point of intersection is 1/2 and that the tangent will intersect at a second point, which can be determined by figuring out the second factor, but that is exactly my problem. I cannot remember how to determine the other factor for a cubic trinomial that cannot be simplified into a quadratic. I believe mine cannot 0=x^3 -(3/4)x + 1/4.
Honestly, it has been a while since I studied these earlier concepts and I used to struggle with factoring. Is there a different theorem or method that can be applied?
is a zero, use synthetic division ...0=x^3 -(3/4)x + 1/4
Code:[1/2].........1.........0........-3/4..........1/4 .......................1/2........1/4..........-1/4 ------------------------------------------------------- ..............1........1/2.......-1/2............0