Hello MHF! First time poster here, the following is my problem:

$\displaystyle 2 log(x) + log(x-1) = 1$

I solved the above by grouping the logs together, resulting in the below:

$\displaystyle log[x^2(x-1)] = 1$

$\displaystyle log[x^3-x^2] = 1$

By removing logs I ended up with:

$\displaystyle x^3 - x^2 = 10$

I simply have no idea how to solve this (it's probably simpler than I might imagine) but the x cubed is confusing me and I cannot find anything I can pull out in common that lets me solve with with an answer of 10 for both brackets or whatever.

Any help is appreciated on the matter.