Substitute x= 3 sec(theta) and simplify

**mathisfun26** · December 7th 2012, 08:26 PM

take the reciprocal of 3/ cos^2 theta?

**MarkFL** · December 7th 2012, 08:43 PM

Yes, so we now have:

$\sqrt{\frac{1}{\cos^2(\theta)}+1}\cdot\frac{\cos^2 (\theta)}{3}=\frac{\cos^2(\theta)\sqrt{\frac{1}{ \cos^2(\theta)}+1}}{3}$

**mathisfun26** · December 7th 2012, 08:45 PM

now what?

**MarkFL** · December 7th 2012, 08:56 PM

You could take the square of the cosine function under the radical and distribute...

**skeeter** · December 8th 2012, 01:33 PM

Originally Posted by mathisfun26

now what? ...

... you have a mess.

whoever came up with this problem should be slapped, or forced to find the decimal representation of $\sqrt{2}$ to one thousand decimal places ... by hand.

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Re: Substitute x= 3 sec(theta) and simplify

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