take the reciprocal of 3/ cos^2 theta?

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- Dec 7th 2012, 08:26 PMmathisfun26Re: Substitute x= 3 sec(theta) and simplify
take the reciprocal of 3/ cos^2 theta?

- Dec 7th 2012, 08:43 PMMarkFLRe: Substitute x= 3 sec(theta) and simplify
Yes, so we now have:

$\displaystyle \sqrt{\frac{1}{\cos^2(\theta)}+1}\cdot\frac{\cos^2 (\theta)}{3}=\frac{\cos^2(\theta)\sqrt{\frac{1}{ \cos^2(\theta)}+1}}{3}$ - Dec 7th 2012, 08:45 PMmathisfun26Re: Substitute x= 3 sec(theta) and simplify
now what?

- Dec 7th 2012, 08:56 PMMarkFLRe: Substitute x= 3 sec(theta) and simplify
You could take the square of the cosine function under the radical and distribute...

- Dec 8th 2012, 01:33 PMskeeterRe: Substitute x= 3 sec(theta) and simplify