try again ...
So I got one problem perfect but this one is just not happening ....
Consider the Quadratic function .
Its vertex is (, ).
Its -intercepts are .
Note: If there is more than one answer enter them separated by commas.
Its -intercept is .
So I am being told -46 and my x intercepts are wrong?
but to find and then when I plug the function into this I got Sorry I cant seem to get my root to cover the whole part over b^2-4ac
My answer are vertex = (5,-46) and
for your vertex use (-b/2a, F( -b/2a)) those will be the coordinates for your vertex.
after that factor your quadratic as skeeter did above and set each binomial equal to zero and solve for x, those will be your roots(or x-intercepts).
for example: X^2-3x-4, when factored becomes (x-4)(x+1) set (x-4) =0 and solve do the same for (x+1). those would give you roots.
and it seems you already know how to do y.