So I got one problem perfect but this one is just not happening ....

Consider the Quadratic function http://webwork.mathstat.concordia.ca...75097b6b91.png.

Its vertex is (, ).

Its http://webwork.mathstat.concordia.ca...dd0b8b8e91.png-intercepts are http://webwork.mathstat.concordia.ca...9019052b81.png .

Note:If there is more than one answer enter them separated by commas.

Its http://webwork.mathstat.concordia.ca...22b824af51.png-intercept is http://webwork.mathstat.concordia.ca...b39caf0291.png .

So I am being told -46 and my x intercepts are wrong?

but to find $\displaystyle k= c-\frac{b^2}{4a} $ $\displaystyle k=-21-\frac{10^2}{4} $ and then when I plug the function into this$\displaystyle \frac{-b+-\sqrt b^2-4ac}{2a}$ I got $\displaystyle -5+-\sqrt46$ Sorry I cant seem to get my root to cover the whole part over b^2-4ac

My answer are vertex = (5,-46) $\displaystyle x=-5+\sqrt46$$\displaystyle x=-5-\sqrt46$ and $\displaystyle y=-21$