im having a really difficult time finding out how to find the verticle asymptote and holes and horizontal asymptote. its really frustrating
for exmaple here are some questions:
thank you in advance
im having a really difficult time finding out how to find the verticle asymptote and holes and horizontal asymptote. its really frustrating
for exmaple here are some questions:
thank you in advance
horizontal asymptote at y = 1/2 ... it's the equation of a line
vertical asymptotes at x = -1 and x = 3 , "hole" at x = -2 ... note the common factor in the numerator and denominator.
OK ... using one of your problems
horizontal asymptote at y = ?
two vertical asymptotes ... where?
one "hole" ... where?
so horizontal asymptote @ y=6
verticle asymptotes at x=+2 and x=-2
the hole would be at.....X^2 would be the only common factor i see. but that would be sqrt0.... so there is no hole?
so after class today i got a good understanding of asymptotes and what not.
only thing that still doesnt make sense is holes. i understand that a hole occurs when you have common factors but what do i do to find the point and what does a hole mean?
A "hole" is really a point discontinuity ... the discontinuity occurs at the x-value that makes the common factor in the numerator and denominator equal to zero.
for example, the function has a "hole" at . the graph of the function will look like the line except for the "hole" at ...
note the graph made on my TI calculator ... see the "hole" ?
sorry, but no ...
there is a hole at x = -1 (the value of x that makes the factor common to the numerator and denominator 0), the y-value of the hole is 3/4
there is one vertical asymptote at x = 3