Do you mean:
(this is how you wrote it)
or
Solve by elimination.
x+2/6 - 3(y+2)/2 = 1
x-2/2 + y-1/3 = 0
For the second one, this is what i did:
multiply by -3 (x-2/2 + y-1/3 = 0)
y = 3x - 4
For the first one:
multiply by 2 (x+2/6 - 3(y+2)/2 = 1)
1/3x + 2/3 -3y -6 = 2
Am i doing this right so far? i'm really confused at this one please help