Solve by elimination.

x+2/6 - 3(y+2)/2 = 1

x-2/2 + y-1/3 = 0

For the second one, this is what i did:

multiply by -3 (x-2/2 + y-1/3 = 0)

y = 3x - 4

For the first one:

multiply by 2 (x+2/6 - 3(y+2)/2 = 1)

1/3x + 2/3 -3y -6 = 2

Am i doing this right so far? i'm really confused at this one please help