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Math Help - linear functions

  1. #1
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    Oct 2007
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    linear functions

    im trying to study for my algebra 2 test tommorow and im not clear on how the answer is:f(x)=2x + 1 to this question: f(x)=3x-5; vertical translation 6 units up followd by a horizontal stretch by factor of 3/2.

    can someone explain the steps to it and are you supposed to do reciprocal for 3/2 to 2/3?
    thanks a lot
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  2. #2
    Junior Member
    Joined
    Oct 2007
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    These functions are written in the form Y=mx+b, where m is the slope and b is the y-intercept. For a vertical translation 6 units up, you simply bump up the y-intercept by 6 units, so -5 + 1 = +1

    As far as horizontal stretch goes, you have to understand slope. By dividing the slope by the included factor (3/2), you end up decreasing the value of M (from 3 to 2). This is considered a horizontal stretch because slope is defined as rise over run (change in y over change in x), so by making your line rise less it will move farther out horizontally.

    If you have a graphing calculator, plug both of those lines in to visualize this because I'm not the best linguist
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