Michele a business consultant has developed a management training course. She has determined that her yearly profit in hundreds of dollars from selling and conducting the course is given by P(x)=-2x^2+60x-25. How many courses should she sell to maximize her profit? what is the maximum profit?
The maximum of a function (or minimum) occurs when the first derivative is equal to zero. So find x such that P'(x)=0. That this will be a maximum is due to the orientation of the quadratic. (Or you can do the second derivative test.) Then use that value of x in the function P to find the maximum profit.Originally Posted by batman123
Michele a business consultant has developed a management training course. She has determined that her yearly profit in hundreds of dollars from selling and conducting the course is given by P(x)=-2x^2+60x-25. How many courses should she sell to maximize her profit? what is the maximum profit?
-Dan
This is a parabola with a maximum (notice the negative number in front). The max/min of a parabola is given by,
Michele a business consultant has developed a management training course. She has determined that her yearly profit in hundreds of dollars from selling and conducting the course is given by P(x)=-2x^2+60x-25. How many courses should she sell to maximize her profit? what is the maximum profit?
, in this case we have,
. Substitute that into the equation to get,
Q.E.D.
  |
LinkBack URL
About LinkBacks