Please explain the domain and range of a function:

f(x)= square root 6-2x

What is the domain and what is the range :confused:

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- Mar 5th 2006, 06:56 AMbatman123Domain and Range
Please explain the domain and range of a function:

f(x)= square root 6-2x

What is the domain and what is the range :confused: - Mar 5th 2006, 09:37 AMCaptainBlackQuote:

Originally Posted by**batman123**

function is defined.

The function:

$\displaystyle

f(x)=\sqrt{6-2x}

$

is defined whenever $\displaystyle 6-2x \ge 0$, which is equivalent to $\displaystyle x \le 3$. Thus the

domain of $\displaystyle f$ is the set of all real numbers $\displaystyle x \le 3$.

The range of a function is the set (in this case of real numbers)of values

which can be a value taken by the function for sone $\displaystyle x$ in its domain.

In this case any $\displaystyle y \ge 0$ can be written as $\displaystyle y=f(x)$ for

some $\displaystyle x \le 3$, so the range of $\displaystyle f$ is the set of all $\displaystyle y \ge 0$.

RonL - Mar 5th 2006, 09:44 AMThePerfectHackerQuote:

Originally Posted by**batman123**