Attachment 25905

factor this please

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- Nov 24th 2012, 06:33 PMmathisfun26factor completely
Attachment 25905

factor this please - Nov 24th 2012, 06:38 PMjakncokeRe: factor completely
I'm having a hardtime reading the image.

Is it

$\displaystyle \frac{1}{2}x^{\frac{-1}{2}}(3x+1)^{1/2} - \frac{3}{4}x^{\frac{1}{2}} (3x+1)^{\frac{-1}{2}} $ ? - Nov 24th 2012, 06:42 PMmathisfun26Re: factor completely
yes it is

- Nov 24th 2012, 06:46 PMMarkFLRe: factor completely
The image is a bit hard to read, but I presume you have:

$\displaystyle \frac{1}{2}x^{-\frac{1}{2}}(3x+1)^{\frac{1}{2}}-\frac{3}{4}x^{ \frac{1}{2}}(3x+1)^{-\frac{1}{2}}$

First, look at the constant factors...they have $\displaystyle \frac{1}{4}$ as factors. Then look at the variable factors and pull out the factors with the smallest exponents.

What do you get? - Nov 24th 2012, 06:49 PMmathisfun26Re: factor completely
i get 1/4x^-1/2(3x+1)^-1/2

how do you guys write it perfectly?? - Nov 24th 2012, 06:51 PMjakncokeRe: factor completely
We use a typesetting language called latex. Below is the way to write a simple equation in latex. Using Latex, you can write math and it is beautiful and easy to read

The below link shows you how to use Latex.

Introducing LaTeX Math Typesetting - Nov 24th 2012, 06:52 PMMarkFLRe: factor completely
Yes, that's what will be out front, and what will be the factor left within parentheses?

We are using $\displaystyle \LaTeX$ to write the math expressions. Do a search here and online to find out how to use it. It is fairly straightforward. - Nov 24th 2012, 06:56 PMmathisfun26Re: factor completely
$\displaystyle \frac{1}{4}x^{-1/2}(3x+1)^{-1/2} $

thanks! - Nov 24th 2012, 06:58 PMjakncokeRe: factor completely
- Nov 24th 2012, 07:02 PMMarkFLRe: factor completely
A neat feature here is that if you hover your mouse cursor over an expression written in LaTeX code, you will see the code used to generate the expression.

- Nov 24th 2012, 07:10 PMmathisfun26Re: factor completely
$\displaystyle \frac{1}{2} (3x+1)$ this is what i got when i divided it by the first term i'm not sure how to do it after that

- Nov 24th 2012, 07:30 PMMarkFLRe: factor completely
You are close...the first term within the parentheses would be:

$\displaystyle 2(3x+1)$

What do you get for the second term? - Nov 24th 2012, 07:35 PMmathisfun26Re: factor completely
why would it be 2??

- Nov 24th 2012, 07:40 PMmathisfun26Re: factor completely
i got -3x for the second

- Nov 24th 2012, 07:42 PMMarkFLRe: factor completely
It would be 2 because:

$\displaystyle \frac{\frac{1}{2}}{\frac{1}{4}}=2$

You are correct with the second term being $\displaystyle -3x$. So, put it all together, and what do you have?