$\displaystyle \frac{1}{4}x^{-1/2}(3x+1)^{-1/2}[3x+2] $ if the question said no negative exponents in the final answer how would it be?
[QUOTE=MarkFL2;754391]The image is a bit hard to read, but I presume you have:
$\displaystyle \frac{1}{2}x^{-\frac{1}{2}}(3x+1)^{\frac{1}{2}}-\frac{3}{4}x^{ \frac{1}{2}}(3x+1)^{-\frac{1}{2}}$
First, look at the constant factors...they have $\displaystyle \frac{1}{4}$ as factors. Then look at the variable factors and pull out the factors with the smallest exponents.
quick question how did u get 1/4 from the factors of 1/2 and 3/4