Where you have:
-116 = 29y
-116/-29 = y
You should have:
-116 = 29y
-116/29=y
Do you see why, and how this fixes your error?
For the second system, multiply the first equation by 12 and the second by 6 to get:
Can you finish?
I have a few questions on systems of linear equations. I tried them and either i get a negative answer that should be positive, or vice versa. I checked the answers on the back of the textbook and answers were different than mine. Please help.
Solve by elimination.
38=2x-5y
75=7x-3y
What i did to solve:
-7(38=2x-5y) 2((75=7x-3y)
-266=-14x+35y 150=14x-6y
150= 14x-6y
+(-266= -14x+35y)
-116 = 29y
-116/-29
y= 4
I use the same process to find x. x=-9
my answer (x,y) = (-9,4)
textbook answer (x,y) = (9,-4)
what did i do differently? where did i go wrong? help
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Solve by elimination:
x/3+y/4=2
2x/3-y/2=0
how do i break this down to solve?
i tried and ended up with y=2, text said x,y = 3,4
Where you have:
-116 = 29y
-116/-29 = y
You should have:
-116 = 29y
-116/29=y
Do you see why, and how this fixes your error?
For the second system, multiply the first equation by 12 and the second by 6 to get:
Can you finish?