Hello Guys
I Need some Help in Fonctions
The function f is set to R:
F (x) = 3x 4x ^ 2 -1/2
1. Calculate f (-1), f (-1/2), f (1 / 2) and f (1) { i did this)
2. Proving that the equation f (x) = 0 admits three distinct solutions, ranging from
-1 And 1
3. Let x = cos (alfa)
Express cos3 (alfa), according to cos (alfa)
2. Determiner solutions of the equation f (x) = 0
my second question for x between 0 and 2pie, solve cos(4x)=sin(2x) {edit : i solved this No need to solve it again lol
and my last question :
Prove that the equation sinx -1/2 = 0
In admits } 0, 2 (pi) {a unique solution
Thanks In Advance
Hello,
you mentioned 3 (three) distinct solutions. So I assume that your function reads:
You have to solve the equation f(x) = 0:
. A product of two factors equals zero if one factor equals zero:
Solve the equations for x. I've got:
These three solutions belong to [-1, 1]