The arithmetic series I have begins with 100, and increases in increments of 100. (so d=100, a1=100, a2=200, a3=300, etc)
The geometric series I have begins with 2 and increases in increments of 2. so r=2, a1=2, a2=4, a3=8, etc.)
I know the formulas an=d(n-1) + a1
and an=a1r^n-1
...but I don't know how to apply them to find at what term n the two series will meet.
Help, please?
I am very, very thankful to you both for your replies!!
I agree that the found equation does not look easy to solve, and am seriously questioning whether I wrote the problem down wrong. >_<
The 8 I wrote down looked kind of like a 6 (which would make the geometric series an arithmetic series), but the two equations would clearly never meet if one was increasing in increments of two and the other in increments of 1000. So, I guess I'll just have to wait it out till class on Friday.
Sorry for taking up your time, and again, THANK YOU^whatever the answer to this problem is.