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Thread: Nonlinear Systems of Equations Problem Exercies

  1. #1
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    Nonlinear Systems of Equations Problem Exercies

    Nonlinear Systems of Equations Problem ExerciesNonlinear Systems of Equations Problem - YouTube
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  2. #2
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    Re: Nonlinear Systems of Equations Problem Exercies

    To begin with $\displaystyle (2x)^2$ is NOT equal to $\displaystyle 2x^2$.

    If $\displaystyle y^2= x^2- 1$ y is NOT equal to $\displaystyle x- 1$

    You seem to be having extreme difficulty with square roots! In general [itex]\sqrt{ax^2+ b[/tex] is NOT equal to ax+ b.
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  3. #3
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    Re: Nonlinear Systems of Equations Problem Exercies

    13. $\displaystyle y = \sqrt{x}$ , $\displaystyle y = 2x$

    $\displaystyle 2x = \sqrt{x}$

    $\displaystyle (2x)^2 = (\sqrt{x})^2$

    $\displaystyle 4x^2 = x$

    $\displaystyle 4x^2 - x = 0$

    $\displaystyle x(4x-1) = 0$

    $\displaystyle x = 0 \, , \, x = \frac{1}{4}$


    19.

    $\displaystyle x^2 + y^2 = 1$

    $\displaystyle y = x $

    substitute x for y ...

    $\displaystyle x^2 + x^2 = 1$

    $\displaystyle 2x^2 = 1$

    $\displaystyle x^2 = \frac{1}{2}$

    $\displaystyle x = \pm \sqrt{\frac{1}{2}}$

    btw, regarding your attempt ... note that $\displaystyle \sqrt{-x^2+1} \ne -x + 1$ get that out of your head, NOW.


    23.

    $\displaystyle 2x^2 - y^2 = 1$

    $\displaystyle x^2 - 2y^2 = -1 $

    multiply the second equation by $\displaystyle -2$ to eliminate the x terms ...

    $\displaystyle 2x^2 - y^2 = 1$

    $\displaystyle -2x^2 + 4y^2 = 2$

    ---------------------------

    $\displaystyle 3y^2 = 3$

    $\displaystyle y = \pm 1 $
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    Re: Nonlinear Systems of Equations Problem Exercies

    It all worked out I got it now. I over emphasized it now. How you guys upload your work on here like that ^? Is that a software or a tool on here? How do I access it?
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  5. #5
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    Re: Nonlinear Systems of Equations Problem Exercies

    it's called Latex ...

    LaTeX Help
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