Not sure how to solve this trig problem dealing with the three roots of one

**derek1008** · November 11th 2012, 09:37 AM

Solve. z to the third power -1=0

**richard1234** · November 11th 2012, 10:29 AM

$z^3 = 1$

z can be any of three roots of unity: $1$ , $e^{i \frac{2\pi}{3}}$ , and $e^{i \frac{4\pi}{3}}$ (which correspond to three evenly spaced points on the unit circle).

**derek1008** · November 11th 2012, 11:02 AM

So is 1/2 the answer?

**richard1234** · November 11th 2012, 11:49 AM

Originally Posted by derek1008

So is 1/2 the answer?

...

Where did you get 1/2 from? Is (1/2)^3 - 1 really equal to zero?

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