maximise Z=2X+3Y such that X+Y<=10 2X+Y<=6
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Get the intersection of the two inequalities, x +y = 10 --------------(1) 2x +y = 6 --------------(2) (2) minus (1), x = -4 So, using (1), y = 10 -x = 10 -(-4) = 14 Therefore, to maximize z, x must be -4 and y must be 14. ---------answer.
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